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Proof step 62 from proof gcd-rec-sub-03 (previous step)

i0 < i, 0 < i, i0 ≤ 0 ⊦ gcd(i, i0 + i) = gcd(i0 + i, i0), i = 0, i0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 63:
0 < i, i0 < i, i0 < 0 ⊦ gcd(i, i0 + i) = gcd(i0 + i, i0), i = 0, i0 = 0

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs% ⊦ i ≠ j → (i ≤ j ↔ i < j); (s)