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Proof step 69 from proof gcd-rec-sub-03 (previous step)

abs(i0 + i) = abs(i) - abs(i0), abs(i0) < abs(i), 0 < i, i0 < i, i0 < 0 ⊦ gcd(abs(i), abs(i0 + i)) = gcd(abs(i0 + i), abs(i0)), i = 0, i0 = 0

User applied rule insert equation

And obtained the following new goals

Proof step 70:
i0 < 0, i0 < i, 0 < i, abs(i0) < abs(i) ⊦ gcd(abs(i), abs(i) - abs(i0)) = gcd(abs(i) - abs(i0), abs(i0)), i = 0, i0 = 0

Rule argument

pos: left 1 flags: discard

Additional information