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Proof step 84 from proof gcd-rec-sub-03 (previous step)

0 < i, i0 < i, i0 < 0, 0 < abs(i0) - abs(i), abs(i0) - abs(i) < abs(i0) ⊦ gcd(abs(i), abs(i0) - abs(i)) = gcd(abs(i0), abs(i0) - (abs(i0) - abs(i))), i = 0, i0 = 0, abs(i0) < abs(i)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 85:
⊦ i - (i - j) = j
Proof step 86:
abs(i0) - abs(i) < abs(i0), 0 < abs(i0) - abs(i), i0 < 0, i0 < i, 0 < i ⊦ gcd(abs(i), abs(i0) - abs(i)) = gcd(abs(i0), abs(i)), i = 0, i0 = 0, abs(i0) < abs(i)

Rule argument

spec: int-abs name: sub-same seq: ⊦ i - (i - j) = j subst: [j, i] → [abs(i), abs(i0)] flags: <all paths>

Additional information

Used terms: abs(i), abs(i0)