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Proof step 1 from proof gcd-same-02 (conclusion)

⊦ gcd(abs(i), abs(i)) = abs(i)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ i ≠ 0 → gcd(i, i) = abs(i)

Rule argument

spec: <toplevel> name: gcd-same seq: ⊦ i ≠ 0 → gcd(i, i) = abs(i) subst: [i] → [abs(i)] flags: <all paths>

Additional information

Used simplifier rules: gcd-zero: ⊦ gcd(0, 0) = 0;% ⊦ abs(i) = 0 ↔ i = 0; (s)% ⊦ abs(abs(i)) = abs(i); (s) Used terms: abs(i)