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Proof step 10 from proof gcd-zero-05 (previous step)

gcd(i, j) + gcd(i0, j0) = 0, 0 ≤ gcd(i, j) ⊦ gcd(i, j) = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
gcd(i, j) + gcd(i0, j0) = 0, 0 < gcd(i, j) ⊦ gcd(i, j) = 0

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ i ≠ j → (i ≤ j ↔ i < j); (s)