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Proof step 2 from proof max_prime_divisor-abs-01 (previous step)

2 ≤ i ⊦ abs(max_prime_divisor(i)) = max_prime_divisor(i), prime(i)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: max_prime_divisor-nls-zero: ⊦ ¬ prime(i) ∧ 2 ≤ i → ¬ max_prime_divisor(i) < 0;% ⊦ i ≤ j ↔ ¬ j < i; (ss)% ⊦ abs(i) = i ↔ 0 ≤ i; (s)