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Proof step 2 from proof max_prime_divisor-abs (previous step)

2 ≤ i ⊦ abs(i / max_prime_divisor(i)) = i / max_prime_divisor(i), prime(i)

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: max_prime_divisor-not-zero: ⊦ ¬ prime(i) ∧ 2 ≤ i → max_prime_divisor(i) ≠ 0;%max_prime_divisor-abs-01: ⊦ ¬ prime(i) ∧ 2 ≤ i → abs(max_prime_divisor(i)) = max_prime_divisor(i);% ⊦ 0 < j → abs(j) = j; (s)%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%forward-le: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward) from specification int-abs%j ≠ 0 ⊦ abs(i / j) = abs(i) / abs(j); (s)