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Proof step 2 from proof max_prime_divisor-divides-01 (previous step)

2 ≤ i ⊦ i % max_prime_divisor(i) = 0, prime(i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
0 < i, 2 ≤ i, 0 ≤ i ⊦ i % max_prime_divisor(i) = 0, prime(i)

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%forward-le: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward) from specification int-abs