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Proof step 1 from proof max_prime_divisor-divides-02 (conclusion)
⊦ ¬ j | i ∧ prime(j) ∧ ¬ prime(i) ∧ 2 ≤ i → ¬ j | i / max_prime_divisor(i)
System applied rule normalize
And obtained the following new goals
Proof step 2
:
prime(j), j | i / max_prime_divisor(i), 2 ≤ i ⊦ prime(i), j | i
Rule argument
Additional information