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Proof step 1 from proof max_prime_divisor-divides-03 (conclusion)

⊦ ¬ prime(i) ∧ 2 ≤ i ∧ prime(j) ∧ j | i ∧ j ≠ max_prime_divisor(i) → j | i / max_prime_divisor(i)

System applied rule normalize

And obtained the following new goals

Rule argument

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