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Proof step 7 from proof max_prime_divisor-divides-03 (previous step)

0 < i, prime(j), j | i, 2 ≤ i, 0 ≤ i, ¬ prime(i) ∧ 2 ≤ i → (∃ i0. max_prime_divisor(i) * i0 = i) ⊦ j = max_prime_divisor(i), prime(i), j | i / max_prime_divisor(i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information