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Proof step 5 from proof max_prime_divisor-divides (previous step)

0 < i, 0 ≤ i, 2 ≤ i, ¬ prime(i) ∧ 2 ≤ i → (∃ j. prime(j) ∧ j | i ∧ j < i ∧ (∀ j0. j < j0 ∧ j0 < i ∧ prime(j0) → ¬ j0 | i)) ⊦ prime(i), max_prime_divisor(i) | i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
0 < i, j < i, prime(j), j | i, 2 ≤ i, 0 ≤ i, ∀ j0. j < j0 ∧ j0 < i ∧ prime(j0) → ¬ j0 | i ⊦ prime(i), max_prime_divisor(i) | i

Proof step 5 from proof max_prime_divisor-divides (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information