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Proof step 12 from proof max_prime_divisor-ge2 (previous step)

max_prime_divisor(i) * i0 = i, i0 < 2, 0 < i, i0 < i, 2 ≤ i, 0 ≤ i ⊦ prime(i)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 13:
⊦ 0 < j → (j < 2 ↔ j = 1)
Proof step 14:
max_prime_divisor(i) * i0 = i, i0 < i, 0 < i, i0 < 2, 0 ≤ i, 2 ≤ i ⊦ 0 < i0, prime(i)
Proof step 20:
max_prime_divisor(i) * i0 = i, i0 = 1, i0 < i, 0 < i, 0 < i0, 0 ≤ i, 2 ≤ i ⊦ prime(i)

Rule argument

spec: int-basic1 name: two-ls seq: ⊦ 0 < j → (j < 2 ↔ j = 1) subst: [j] → [i0] flags: <all paths>

Additional information

Used terms: i0