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Proof step 11 from proof max_prime_divisor-nls-03 (previous step)

0 < i, j < i / j, j < i, prime(i / j), prime(j), 0 ≤ i, 2 ≤ i, ∀ j0. j < j0 ∧ j0 < i ∧ prime(j0) → ¬ j0 | i, ∃ i0. j * i0 = i ⊦ prime(i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
j < j * i0, j < i0, 0 < j * i0, prime(j), prime(i0), 2 ≤ j * i0, 0 ≤ j * i0, ∀ j0. j < j0 ∧ j0 < j * i0 ∧ prime(j0) → ¬ j0 | j * i0 ⊦ prime(j * i0)

Rule argument

Additional information

Used simplifier rules: forward-le: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward) from specification int-abs%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%j ≠ 0 ⊦ (i * j) / j = i; (s)%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult% ⊦ i * 0 = 0; (s)