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Proof step 2 from proof not-less-gcd (previous step)

i < gcd(i, j), 0 < i ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
1 < gcd(i, j), i < gcd(i, j), 0 < i, 0 < gcd(i, j) ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-pos: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward) from specification int-basic1