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Proof step 13 from proof prime-163 (previous step)

163 % i = 0, 0 < i, 1 < i, i < 12, i * i ≤ 163 ⊦ i = 12, 2 ≤ i ∧ i < 10

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 14:
⊦ i ≠ j -1 → (i < j ↔ i < j -1)
Proof step 15:
163 % i = 0, i < 12 -1, 1 < i, 0 < i, i * i ≤ 163 ⊦ i = 12, i = 12 -1, 2 ≤ i ∧ i < 10

Rule argument

spec: int-basic1 name: ls-rec seq: ⊦ i ≠ j -1 → (i < j ↔ i < j -1) subst: [j, i] → [12, i] flags: <all paths>

Additional information

Used terms: 12, i