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Proof step 7 from proof prime-317 (previous step)

317 % i = 0, 0 < i, 1 < i, i * i ≤ 317 ⊦ abs(18) ≤ abs(i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
317 % i = 0, 1 < i, 0 < i, i < 18, i * i ≤ 317 ⊦

Rule argument

Additional information

Used simplifier rules: forward-pos: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward) from specification int-basic1% ⊦ i ≤ j ↔ ¬ j < i; (ss)% ⊦ 1 < i → abs(i) = i; (s)