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Proof step 14 from proof prime-43 (previous step)

43 % i = 0, 1 < i, 0 < i, i < 5, i * i ≤ 43 ⊦ i = 6, i = 5

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 15:
⊦ i < j ↔ i +1 = j ∨ i +1 < j
Proof step 16:
43 % i = 0, 0 < i, 1 < i, i * i ≤ 43, i +1 = 5 ∨ i +1 < 5 ⊦ i = 5, i = 6

Rule argument

spec: int-basic1 name: lsrec seq: ⊦ i < j ↔ i +1 = j ∨ i +1 < j subst: [j, i] → [5, i] flags: <all paths>

Additional information

Used terms: 5, i