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Proof step 7 from proof prime-7 (previous step)

7 % i = 0, 0 < i, 0 ≤ i, i * i ≤ 7, 3 ≤ i ⊦ 3 * 3 ≤ i * i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ i * i ≤ j * j ↔ abs(i) ≤ abs(j)

Rule argument

spec: int-mult name: square-le seq: ⊦ i * i ≤ j * j ↔ abs(i) ≤ abs(j) subst: [j, i] → [i, 3] flags: <all paths>

Additional information

Used simplifier rules: ⊦ 0 < j → abs(j) = j; (s)% ⊦ i ≤ j ↔ ¬ j < i; (ss)% ⊦ i ≤ j → ¬ j < i; (s) Used terms: i, 3