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Proof step 9 from proof prime-7 (previous step)

7 % i = 0, 1 < i, 0 < i, i * i ≤ 7 ⊦ 3 ≤ i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
7 % i = 0, 0 < i, 1 < i, i < 3, i * i ≤ 7 ⊦

Rule argument

Additional information

Used simplifier rules: forward-pos: ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j; (forward) from specification int-basic1% ⊦ i ≤ j ↔ ¬ j < i; (ss)