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Proof step 14 from proof prime-def-mod (previous step)

0 < j, 1 < j, ∀ i. 1 < i ∧ i * i ≤ j → j % i ≠ 0 ⊦ 2 ≤ j ∧ (1 < i ∧ i < j → ¬ i | j)

User applied rule cut formula

And obtained the following new goals

Proof step 15:
1 < j, 0 < j, ∀ i. 1 < i ∧ i * i ≤ j → j % i ≠ 0 ⊦ j = 1, 2 ≤ j ∧ (1 < i ∧ i < j → ¬ i | j)

Rule argument

fma: j = 1

Additional information

Used formulas: j = 1