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Proof step 15 from proof prime-def-prime (previous step)

1 < i, 0 < i, ∀ j. prime(j) ∧ j * j ≤ i → ¬ j | i, ∀ i0. i→n(i0) < i→n(i) → 0 < i0 ∧ 1 < i0 ∧ (∀ j. prime(j) ∧ j * j ≤ i0 → ¬ j | i0) → prime(i0) ⊦ 2 ≤ i ∧ (1 < i0 ∧ i0 < i → ¬ i0 | i)

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: divides seq: ⊦ i | j ↔ (∃ i0. i * i0 = j) subst: [j, i] → [i, i0] flags: <all paths>

Additional information

Used terms: i, i0