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Proof step 4 from proof prime-def-prime (
previous step
)
1 < i, 0 < i, prime(i) ⊦ prime(i) ↔ (∀ j. prime(j) ∧ j * j ≤ i → ¬ j | i)
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 5
:
0 < i, 1 < i, prime(i), prime(j), j | i, j * j ≤ i ⊦
Rule argument
Additional information