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Proof step 5 from proof prime-two (previous step)
| 0 < j, ∀ i. 1 < i ∧ i < 2 * j → ¬ i | 2 * j ⊦ j = 1 |
Heuristic quantifier closing applied rule all left
And closed the goal!
Rule argument
pos: left 2 terms: 2Additional information
Used simplifier rules:
div-mult: ⊦ i | i * j;% ⊦ 0 < i ∧ 0 ≤ j → ((* j) < (* i) * i0 ↔ j / i < i0); (s)%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult% ⊦ i < j ↔ ¬ j ≤ i; (ss)% ⊦ 0 < i → (i ≤ 1 ↔ i = 1); (s)
Used terms: 2