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Proof step 10 from proof square-neq-pos-h (previous step)

i0 * i * i0 = j0 * j0, gcd(i * i0, j0) = 1, 0 < i * i0, prime(i), 0 ≤ j0 ⊦ i = 0

User applied rule cut formula

And obtained the following new goals

Proof step 11:
i0 * i * i0 = j0 * j0, gcd(i * i0, j0) = 1, 0 < i * i0, prime(i), i | j0, 0 ≤ j0 ⊦ i = 0
Proof step 13:
i0 * i * i0 = j0 * j0, gcd(i * i0, j0) = 1, 0 < i * i0, prime(i), 0 ≤ j0 ⊦ i = 0, i | j0

Rule argument

fma: i | j0

Additional information

Used formulas: i | j0