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Proof step 14 from proof square-neq-pos-h (previous step)

i0 * i * i0 = j0 * j0, gcd(i * i0, j0) = 1, 0 < i * i0, prime(i), 0 ≤ j0 ⊦ i = 0, i | j0, i | j0 * j0

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 1 flags: rotate, discard

Additional information

Used simplifier rules: prime-divides: ⊦ prime(i) → (i | j * j0 ↔ i | j ∨ i | j0);%div-mult: ⊦ i | i * j;%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult