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Proof step 16 from proof square-neq-pos-h (previous step)

j * j = i * j0 * j0, gcd(j, j0) = 1, 0 < j, prime(i), 0 ≤ j0 ⊦ i | j, i | j * j

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 1 flags: discard

Additional information

Used simplifier rules: prime-divides: ⊦ prime(i) → (i | j * j0 ↔ i | j ∨ i | j0);%div-zero: ⊦ i | i;%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult