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Proof step 3 from proof square-neq-pos-h (previous step)

j * j = i * j0 * j0, gcd(j, j0) = 1, 0 < j, prime(i), 0 ≤ j0 ⊦

User applied rule cut formula

And obtained the following new goals

Proof step 4:
j * j = i * j0 * j0, gcd(j, j0) = 1, 0 < j, prime(i), i | j, 0 ≤ j0 ⊦
Proof step 15:
j * j = i * j0 * j0, gcd(j, j0) = 1, 0 < j, prime(i), 0 ≤ j0 ⊦ i | j

Rule argument

fma: i | j

Additional information

Used formulas: i | j