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Proof step 14 from proof square-neq-prime (previous step)

j * j = i * j0 * j0, prime(i), j ≤ 0, j ≠ 0 ∨ j0 ≠ 0 ⊦ j < 0 ∧ 0 ≤ j0

User applied rule cut formula

And obtained the following new goals

Proof step 15:
j * j = i * j0 * j0, prime(i), j ≤ 0, j ≠ 0 ∨ j0 ≠ 0 ⊦ j = 0, j < 0 ∧ 0 ≤ j0

Rule argument

fma: j = 0

Additional information

Used simplifier rules: prime-small: ⊦ j < 2 → ¬ prime(j);%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult%commutativity: ⊦ i * j = j * i; from specification int-mult% ⊦ i * j = 0 ↔ i = 0 ∨ j = 0; (ws) Used formulas: j = 0