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Proof step 1 from proof max-01 (conclusion)

⊦ max(i, j) < j0 ↔ i < j0 ∧ j < j0

Heuristic weak cut applied rule cut formula

And closed the goal!

Rule argument

fma: i < j

Additional information

Used simplifier rules: Max-right: ⊦ j < i → max(j, i) = i;%Max-left: ⊦ ¬ j < i → max(j, i) = j;%lf-07: ⊦ ¬ i < i0 ∧ j < i0 → j < i; (forward) from specification int-basic1%lf-08: ⊦ ¬ i < j ∧ ¬ i0 < i → ¬ i0 < j; (forward) from specification int-basic1%lf-04: ⊦ ¬ j < i ∧ j < i0 → i < i0; (forward) from specification int-basic1% ⊦ i < j ∧ ¬ i0 < j → ¬ i0 < i; (s) Used formulas: i < j