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Proof step 2 from proof max-03 (previous step)

i < j0, j < j0 ⊦ max(i, j) < j0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: max-01: ⊦ max(i, j) < j0 ↔ i < j0 ∧ j < j0;%lf-04: ⊦ ¬ j < i ∧ j < i0 → i < i0; (forward) from specification int-basic1%lf-07: ⊦ ¬ i < i0 ∧ j < i0 → j < i; (forward) from specification int-basic1