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Proof step 5 from proof max-a (previous step)

j < j0, i < j0 ⊦ j0 = max(max(i, j), j0)

Heuristic weak cut applied rule cut formula

And closed the goal!

Rule argument

fma: max(i, j) < j0

Additional information

Used simplifier rules: Max-right: ⊦ j < i → max(j, i) = i;%Max-left: ⊦ ¬ j < i → max(j, i) = j;%max-01: ⊦ max(i, j) < j0 ↔ i < j0 ∧ j < j0;% ⊦ ¬ i < j → (i = j ↔ ¬ j < i); (ss)%lf-01: ⊦ i < j ∧ j < i0 → i +1 < i0; (forward) from specification int-basic1%trans: ⊦ i < j ∧ j < j0 → i < j0; (forward) from specification int-basic1%lf-07: ⊦ ¬ i < i0 ∧ j < i0 → j < i; (forward) from specification int-basic1%lf-04: ⊦ ¬ j < i ∧ j < i0 → i < i0; (forward) from specification int-basic1 Used formulas: max(i, j) < j0