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Proof step 2 from proof min-01 (previous step)

j0 < i, j0 < j ⊦ j0 < min(i, j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
j0 < j, j0 < i, min(i, j) < j, min(i, j) < i ⊦ j0 < min(i, j)

Rule argument

Additional information

Used simplifier rules: lf-04: ⊦ ¬ j < i ∧ j < i0 → i < i0; (forward) from specification int-basic1