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Proof step 4 from proof min-c (previous step)

⊦ min(i, j) = min(j, i), i < j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ j = min(j, i), i < j

Rule argument

Additional information

Used simplifier rules: Min-right: ⊦ ¬ j < i → min(j, i) = i;%min-a: ⊦ min(i, min(j, j0)) = min(min(i, j), j0);