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Proof step 4 from proof abs-eqall (previous step)

⊦ abs(i * j) = abs(i) * abs(j), i < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
0 ≤ i ⊦ abs(i * j) = i * abs(j)

Rule argument

Additional information

Used simplifier rules: ⊦ i < j ↔ ¬ j ≤ i; (ss)% ⊦ ¬ j < 0 → abs(j) = j; (s)