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Proof step 10 from proof abs-ls-same-01 (previous step)

⊦ abs(i) * j < i ↔ ¬ i ≤ 0 ∧ ¬ 0 < j ∨ ¬ 0 ≤ i ∧ ¬ ~1 ≤ j

User applied rule cut formula

And obtained the following new goals

Proof step 11:
j = abs(j) ⊦ abs(i) * j < i ↔ ¬ i ≤ 0 ∧ ¬ 0 < j ∨ ¬ 0 ≤ i ∧ ¬ ~1 ≤ j
Proof step 15:
⊦ abs(i) * j < i ↔ ¬ i ≤ 0 ∧ ¬ 0 < j ∨ ¬ 0 ≤ i ∧ ¬ ~1 ≤ j, j = abs(j)

Rule argument

fma: j = abs(j)

Additional information

Used formulas: j = abs(j)