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Proof step 17 from proof abs-ls-same-01 (previous step)

j = ~1, j < 0 ⊦ abs(i) * j < i ↔ ¬ i ≤ 0 ∨ i ≠ 0 ∧ j ≠ ~1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
⊦ 0 < i + abs(i) ↔ ¬ i ≤ 0

Rule argument

Additional information

Used simplifier rules: minus-one-01: ⊦ i * ~1 = ~ i;%associativity: ⊦ i * j * j0 = (i * j) * j0;%commutativity: ⊦ i * j = j * i;% ⊦ ~ i < j ↔ 0 < j + i; (s)