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Proof step 21 from proof abs-ls-same-01 (previous step)

i + i * j = i * (1 + j), j < 0, i ≤ abs(i) * j ⊦ i = 0, j = ~1

User applied rule insert equation

And obtained the following new goals

Proof step 22:
j < 0, i ≤ abs(i) * j ⊦ i = 0, j = ~1

Rule argument

pos: left 1 flags: discard

Additional information