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Proof step 24 from proof abs-ls-same-01 (previous step)

j < 0, i < 0, i ≤ (0 - i) * j ⊦ i = 0, j = ~1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 25:
j < 0, i < 0, i + i * j ≤ 0 ⊦ i = 0, j = ~1

Rule argument

Additional information

Used simplifier rules: minus-left: ⊦ ~ i * j = ~(i * j);%associativity: ⊦ i * j * j0 = (i * j) * j0;%commutativity: ⊦ i * j = j * i;%forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs%forward-le-04: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward) from specification int-abs% ⊦ i ≤ ~ j ↔ i + j ≤ 0; (s)% ⊦ 0 - i = ~ i; (s)