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Proof step 3 from proof abs-ls (previous step)

j < 0, i < 0, j < j0, j0 < 0, j + 1 < 0, i * j + j0 ≤ 0 ⊦

User applied rule apply lemma

And obtained the following new goals

Proof step 4:
⊦ i < 0 ∧ j < j0 ∧ j < 0 → 0 < i * j + j0

Rule argument

spec: <toplevel> name: modzero-06 seq: ⊦ i < 0 ∧ j < j0 ∧ j < 0 → 0 < i * j + j0 subst: [i, j, j0] → [i, j, j0]

Additional information

Used simplifier rules: ⊦ i ≤ j → (j < i ↔ false); (as) Used terms: i, j, j0