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Proof step 2 from proof eq-same-01 (previous step)

⊦ i * j = i ↔ j = 1, i = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: eq-same: ⊦ i * j = i ↔ i = 0 ∨ j = 1;%associativity: ⊦ i * j * j0 = (i * j) * j0;%commutativity: ⊦ i * j = j * i;%one: ⊦ 1 * i = i;