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Proof step 4 from proof le-neg (previous step)

i < 0, i * j ≤ i * i0 ⊦ i0 ≤ j

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
⊦ i ≤ j ↔ ¬ j < i
Proof step 6:
j < i0, i < 0, i * j ≤ i * i0 ⊦

Rule argument

spec: int-abs name: le-def seq: ⊦ i ≤ j ↔ ¬ j < i subst: [j, i] → [j, i0] flags: <all paths>

Additional information

Used terms: j, i0