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Proof step 4 from proof le-pos (previous step)

0 < i, i * j ≤ i * i0 ⊦ j ≤ i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
i0 < j, 0 < i, i * j ≤ i * i0 ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ i ≤ j ↔ ¬ j < i; (ss)