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Proof step 2 from proof ls-add (previous step)

j1 < j, 0 ≤ j1 ⊦ i0 * j + j1 < j ↔ i0 ≤ 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
j1 < j, 0 < j, 0 ≤ j1 ⊦ i0 * j + j1 < j ↔ i0 ≤ 0

Rule argument

Additional information

Used simplifier rules: forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs