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Proof step 12 from proof mod-neq (previous step)
| i * j = i * j0 + j1, abs(j1) < i, 0 ≤ i ⊦ j1 = 0 |
User applied rule apply lemma
And obtained the following new goals
- Proof step 13:
i * j + j0 = i0 * j + j1, 0 ≤ j0, j0 < j, 0 ≤ j1, j1 < j ⊦ i = i0 ∧ j0 = j1
- Proof step 14:
i * j = i * j0 + j1, abs(j1) < i, 0 ≤ i ⊦ j1 = 0, j * i + 0 = j0 * i + j1 ∧ 0 ≤ 0 ∧ 0 < i ∧ 0 ≤ j1 ∧ j1 < i
Rule argument
spec: <toplevel>
name: modeqp
seq: i * j + j0 = i0 * j + j1, 0 ≤ j0, j0 < j, 0 ≤ j1, j1 < j
⊦ i = i0 ∧ j0 = j1
subst: [i, j, j0, i0, j1] → [j, i, 0, j0, j1]Additional information
Used terms: j, i, 0, j0, j1