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Proof step 5 from proof mod-nls (previous step)

0 < i, i0 < i, j < 0, 0 < (i - 1) * j + i0, 0 ≤ i0 ⊦

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 6:
i = i1 + 1, 0 < i1 * j + i0, j < 0, i0 < i, 0 < i, 0 ≤ i0 ⊦

Rule argument

spec: int-abs name: elim-sub seq: ⊦ i0 = i - j ↔ i = i0 + j subst: [i, j, i0] → [i, 1, i1]

Additional information

Used simplifier rules: ⊦ i0 = i - j ↔ i = i0 + j; (elim) Used terms: i, 1, i1