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Proof step 2 from proof modeqp-02 (previous step)

i * j + j0 = i0 * j + j1, j1 < abs(j), j0 < abs(j), j < 0, 0 ≤ j1, 0 ≤ j0 ⊦ i = i0 ∧ j0 = j1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i * j + j0 = i0 * j + j1, j < 0, j0 + j < 0, j1 + j < 0, 0 ≤ j0, 0 ≤ j1 ⊦ i = i0 ∧ j0 = j1

Rule argument

Additional information

Used simplifier rules: ⊦ i < ~ j ↔ i + j < 0; (s)% ⊦ i < 0 → abs(i) = ~ i; (s)