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Proof step 2 from proof modlep-03 (previous step)

abs(j1) < j, j0 < j, 0 ≤ j0, j * i + j0 ≤ j * i0 + j1 ⊦ i ≤ i0

User applied rule apply lemma

And obtained the following new goals

Proof step 3:
j * i + j0 ≤ j * i0, abs(j0) < j ⊦ i ≤ i0
Proof step 4:
j0 < j, abs(j1) < j, j * i + j0 ≤ j * i0 + j1, 0 ≤ j0 ⊦ i ≤ i0, j * i + (j0 - j1) ≤ j * i0 ∧ abs(j0 - j1) < j

Rule argument

spec: <toplevel> name: modlep-02 seq: j * i + j0 ≤ j * i0, abs(j0) < j ⊦ i ≤ i0 subst: [j, i, j0, i0] → [j, i, j0 - j1, i0]

Additional information

Used terms: j, i, j0 - j1, i0