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Proof step 2 from proof modlsp-04 (previous step)

abs(j0) < abs(j), j < 0, j * i < j * i0 + j0 ⊦ i0 ≤ i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
j * i < j * i0 + j0, j < 0, abs(j0) + j < 0, i < i0 ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ↔ ¬ j < i; (ss)% ⊦ i < ~ j ↔ i + j < 0; (s)% ⊦ 0 - i = ~ i; (s)% ⊦ j < 0 → abs(j) = 0 - j; (s)