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Proof step 3 from proof mods-ls-02 (previous step)

j0 < j, i < i0, 0 < j, 0 ≤ j0, i0 * j ≤ i * j + j0 ⊦

User applied rule apply lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: modlep-01 seq: j * i ≤ j * i0 + j0, abs(j0) < j ⊦ i ≤ i0 subst: [j, i, i0, j0] → [j, i0, i, j0]

Additional information

Used simplifier rules: commutativity: ⊦ i * j = j * i;% ⊦ i < j → (j ≤ i ↔ false); (as)% ⊦ 0 ≤ i → abs(i) = i; (s) Used terms: j, i0, i, j0